11. For some integer m, what is the form of every even integer and odd integer
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for even it is 2m And for odd it is 2m+1
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- Question⇒ For some integer m, what is the form of every even integer and odd integer.
Step-by-step explanation:
- We know that, even integers are 2, 4, 6,…
- So, it can be written in the form of 2m.
- where, m = integer = z [since, integer is reprsented by z]
- or m = ...,- 1,0,1,2,3,...
- Alternate method
- Let 'a' be a positive integer. On dividing 'a' by 2, let m be the quotient and r be the remainder. Then, by Euclid's division algorithm, we have
- a = 2m + r, where a ≤ r < 2 i.e.,r = 0 and r = 1.
- ⇒ a = 2m or a = 2m + 1
- when, a = 2m for some integer m, then clearly a is even .
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