Question

11 g ram of a gas occupies 5.6 litres of volume at STP the gas is

Answer 1

Molar gas volume at stp is :

1 mole = 22.4 litres

The moles of the gas is :

Moles = 5.6 / 22.4 = 0.25 moles

Moles = mass / molar mass

Molar mass = mass / moles

Molar mass = 11 / 0.25 = 44g/mol

The gas with a molar mass of 44g/mol is Carbon (iv) oxide.

This is given by :

CO₂

C = 12

O₂ = 16 × 2 = 32

12 + 32 = 44g/mol