Question

11. गुणनखण्ड कीजिए :x^6 - 7x^3-
8.​

Answer 1

Answer: (x-2) (x^2+2x+4) (x+1) (x^2-x+1)

Step-by-step explanation:

x^6 - 7x^3- 8

(x^3) ^2 - 7x^3-8

Put x^3= y

y^2-7y-8

= y^2- 8y + y -8

= y(y-8) +1(y-8)

= (y-8) (y+1) ,

Now, put y= x^3,

= (x^3-8) (x^3+1)

= (x^3-2^2) (x^3+1^3)

Applying, a^3-b^3= (a-b)(a^2+ab+b^2)

a^3+b^3= (a+b)(a^2-ab+b^2)

= (x-2) (x^2+2x+4) (x+1) (x^2-x+1)