Question

11 GRAM GAS ACCUPY 5.6 L OF VOLUME AT STO THE GAS IS

Answer 1

Answer:

Use this formula :

Wt in gm/Molar mass = Vol. at STP/22.4

Now,

11/Molar mass = 5.6/22.4

11/Molar mass = 1/4

Therefore , Molar Mass = 44

Thus the gas is CO2

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