11 gram of caco3 is treated with 9.8 grams of h2so4 when precipitate of caso4 are formed with evolution of CO2
calculate the amount of gas evolved if 1 mol gas occupies 22.7 ltr at Stp
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Answer:
Explanation:
mole/sc for caco3 = 0.11
mole/sc for h2so4 = 0.1
mole of co2 = 0.1
volume = 2.27 lt
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