11 gram of gas occupies 5.6 litre of volume at STP, then which gas it is?
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Answered by
30
Hey
Hope it will help you
22.4L of gas = 1mol
1L= 1/22.4 mol
5.6L = 1/4 mol
let molar mass of gas is M then
5.6L = M/4gm =11gm (given)
so M=11*4=44gm
so the gas is N2O
Hope it will help you
22.4L of gas = 1mol
1L= 1/22.4 mol
5.6L = 1/4 mol
let molar mass of gas is M then
5.6L = M/4gm =11gm (given)
so M=11*4=44gm
so the gas is N2O
Answered by
1
Answer:the answer can be co2 or N2O
Explanation:
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