11 gram of gas occupy 5.6 liter of volume at stp the gas is ???
siril:
ANY GAS at STP occupies 22.4 litres
the question should have been "calculate the mass of the gas, 11 grams of which occupies 5.6 litres
Answers
Answered by
1
N2O is the gas that occupy 5.6 litres at STP
ANY GAS occupies 22.4 litres at STP, the volume changes depending upon the number of moles taken
ohk*
bhai n2o hi vo gas h
chahe to google pe check kar le
it co2
this is an iit question
no co2is not
are bhai....it is a universal fact that "ANY GAS at STP occupies 22.4 litres"
please go through 11th class chemistry ncert part 1 - first lesson ...thoroughly
Answered by
1
At STP, 1mole of any gas occupies 22.4 litres of volume.
This volume is also called Molar volume.
→Take the example of CO2, whose molecular weight is 44 grams.
This means that 1mole of CO2 weighs 44 grams and as said above, it occupies 22.4 litres of volume at STP.
So, 5.6 litres means 0.25 moles...which in turn means 1/4 times 44 =11grams
Therefore 5.6 litres of CO2 which is 0.25 moles weighs 11 grams at STP.
The same result comes in case of N2O.
"1mole of any gas at STP occupies 22.4 litres of volume"
This volume is also called Molar volume.
→Take the example of CO2, whose molecular weight is 44 grams.
This means that 1mole of CO2 weighs 44 grams and as said above, it occupies 22.4 litres of volume at STP.
So, 5.6 litres means 0.25 moles...which in turn means 1/4 times 44 =11grams
Therefore 5.6 litres of CO2 which is 0.25 moles weighs 11 grams at STP.
The same result comes in case of N2O.
"1mole of any gas at STP occupies 22.4 litres of volume"
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