Math, asked by sachinabasnet, 7 months ago

11.H.C.F of 2x, 4x²y5 and 8x y zº is
a. 2x b. 4xy. c. 8 d. 8x y z​

Answers

Answered by ksajal567
1

Answer:

option a (2x)

Step-by-step explanation:

When you look carefully 2x us the only coomon factor which is available in all three of the expressions.

In second term 4x²y⁵ has 2x present in it.

In third term you can see 8xyz⁰ has 2x term in it.

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