11 How many tiles whose length and breadth are 12 cm and 5 cm respectively will be 1 needed to cover a rectangular region whose length and breadth are respectively fi 70 cm and 36 cm (ii) 144 cm and 1 m.
Answers
Answer:
Step-by-step explanation:
1) Length of rectangular region= 70 cm
Breadth of rectangular region= 36 cm
Area of rectangular region= length*breadth
= 70*36
= 2520 sq.cm
Length of tile= 12 cm
Breadth of tile= 5 cm
Area of tile= length*breadth
= 12*5
= 60 sq.cm
Number of tile needed to cover rectangular region= Area of rectangular region/ Area of tile
= 2520/60
= 42
42 tiles are needed to cover rectangular region with length 70 cm and breadth 36 cm
2) Length of rectangular region= 144 cm
Breadth of rectangular region= 1 m= 100 cm
Area of rectangular region= length*breadth
= 144*100
= 14400 sq.cm
Length of tile= 12 cm
Breadth of tile= 5 cm
Area of tile= length*breadth
= 12*5
= 60 sq.cm
Number of tile needed to cover rectangular region= Area of rectangular region/ Area of tile
= 14400/60
= 240
240 tiles are needed to cover rectangular region with length 144 cm and breadth 1 m
Answer:
It is given that the tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are given. We found that 240 tiles are required in the 1st case and 42 tiles are required in the 2nd case.
Step-by-step explanation:
We will be using the area of rectangle formula to calculate the area o the rectangular region and the tiles.
We know that, the area of a rectangle is given by length × breadth
(a) Area of rectangular region = 100 × 144
= 14400 cm
Also, area of one tile = 5 × 12
= 60 cm2
The number of tiles needed = Area of the rectangular region / Area of one tile
= 14400 / 60
= 240
Hence, 240 tiles are needed in this case.
(b) Now, area of rectangular region = 70 × 36
= 2520 cm2
Also, area of one tile = 5 × 12
= 60 cm2
The number of tiles needed = Area of the rectangular region / Area of one tile
= 2520 / 60
= 42
Hence, 42 tiles are needed in this case.
Therefore, 240 tiles are required in 1st case and 42 tiles are required in 2nd case.
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