Question

11. If a = -9 and b = -6, show that (a - b) ≠ (b-a)​

Answer 1

Step-by-step explanation:

Step 1                                                 Step 2

(a-b)                                                   (b-a)

(-9-(-6))                                                (-6-(-9))

(-3)                                                         (3)

(-3)≠3

Therefore, (a - b) ≠ (b-a)​

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Answer 2

Given :  a = -9 and b = -6,

To find : Show that  (a - b) ≠ (b-a)​

Solution:

a  = - 9

b = - 6

(a - b) ≠ (b-a)​

LHS  = a - b

= -9  - (-6)

= - 9 + 6

= - 3

RHS =  b - a

= -6 - (-9)

= -6 + 9

= 3

- 3  ≠  3

=> LHS   ≠ RHS

=> (a - b) ≠ (b-a)​

in general

a  - b  =  -(-a + b) = - ( b - a)

(a - b) = -(b - a)

both can be equal iff   both sides are zero

=> if a  =  b

Hence we can say that for all values of  a & b

(a - b) ≠ (b-a)​    if  a  ≠  b

(a - b) = (b-a)​    if  a  =  b

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