Question

11. If a + b = 29 and ab = 2, find the value of
a-b.​

Answer 1

Step-by-step explanation:

Given:-

a + b = 29 and ab = 2

To find:-

find the value of a-b.?

Solution:-

Given that :-

a+b=29

ab=2

we know that

(a-b)²=(a+b)²-4ab

=>(a-b)²=(29)²-4(2)

=>(a-b)²=841-8

=>(a-b)²=833

=>(a-b)=√833

Answer:-

The value of a-b=√833

Used formula:-

• (a-b)²=(a+b)²-4ab

Answer 2

Step-by-step explanation:

(a+b)=29

Square on both sides, we get

(a+b)^2=841

(a^2+b^2+2ab)=841

(a^2+b^2+4ab-2ab)=841

(a^2+b^2–2ab)+4ab = 841

(a-b)^2+4ab=841

{ We know, (a-b)^2 = a^2+b^2–2ab}

(a-b)^2=841–4ab

(a-b)^2 = 841 -(4 × 2)

(a-b)^2 = 841 -8

(a-b)^2= 833

(a-b)=root of 833=+-7root of 17

This is the required answer .

Hope you understood...