Question

11-If a+b+c =0 and a²+b² +c² = 16, find the value of ab + bc + ca

Answer 1

Answer:

-8

Step-by-step explanation:

a+b+c= a^2 + b^2 + c^2 + 2(ab + bc + ca )

0 = 16 + 2(ab + bc + ca )

-16 = 2(ab + bc + ca )

ab + bc + ca = -16/2

ab + bc + ca = -8

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