Question

11. If a body having an initial velocity of 10 m/s, moves with a uniform acceleration of
10 m/s2, then the final velocity when it covers a distance of 3 m is
1) 12.64 m/s 2) 14.2 m/s
3) 13.25 m/s 4) 15.25 m/s
rolea distance of 'X' in​

Answer 1

❒Given :-

Initial velocity (u)of the body is 10m/s

Acceleration of the body(a) is 10 m/s²

Distance covered by the body (s)is 3m

❒Solution:-

As we know that from equations of motion ,

v²- u²= 2as

" v" is the final velocity

"u" is the initial velocity

" a" is the acceleration

"s"is the distance covered

❒Substituting the values ,

v² - u² = 2as

v² - (10)² = 2(10)(3)

v² -100 = 60

v² = 100+60

v² = 160

v = √ 160

v = 12. 64 m/s {1} correct

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❒Know more some formulae :-

• v = u+at
• u = v-at
• s = ut+1/2 at²
• s = vt-1/2 at²
• a = v-u/t
• a = v²-u²/2s
• s = v²-u²/2a

where ,

v = final velocity

u = initial velocity

s = Distance covered

a = accelartion of the body

Answer 2

Hola ⚘⚘

Answer:

• 12.64m/s

Explanation:

Given :

• initial velocity = 10m/s
• acceleration = 10 m/s²
• distance covered by the body= 3m

Tofind:

• final velocity when it covers a distance of 3 m is?

Calculation:

>> v²- u²= 2as

• v = final velocity
• u = initial velocity
• a = acceleration
• s = distance covered

>> v² - u² = 2as

>> v² - (10)² = 2(10)(3)

>> v² -100 = 60

>> v² = 100 + 60

>> v² = 160

>> v = √160

>> v = 12.64 m/s

Hence, Option (1) is correct one [✓]