11. If HCF ( 28, 35 and 343 ) = 7, find the LCM ( 28, 35 and 343).
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Answered by
20
Heya!
Here is yr answer.....
Given,
HCF of 28,35 and 343 = 7
LCM = ??
Now,
According to prime factorization.....
28 = 2² × 7
35 = 5 × 7
343 = 7³
LCM = 7³ × 2² × 5 = 343×4×5 = 6860
Therefore, LCM of 28 , 35 and 343 = 6860
Hope it hlpz...
Here is yr answer.....
Given,
HCF of 28,35 and 343 = 7
LCM = ??
Now,
According to prime factorization.....
28 = 2² × 7
35 = 5 × 7
343 = 7³
LCM = 7³ × 2² × 5 = 343×4×5 = 6860
Therefore, LCM of 28 , 35 and 343 = 6860
Hope it hlpz...
VijayaLaxmiMehra1:
But this process is not right by prime factorization
Answered by
3
We know that,
HCF× LCM=Product of given numbers
7×LCM=28×35×343
7×LCM= 336,140
LCM= 336,140/7
LCM= 48,020
Hence, LCM (28,35,343) is 48,020...
HOPE it helps!!!!✌️
HCF× LCM=Product of given numbers
7×LCM=28×35×343
7×LCM= 336,140
LCM= 336,140/7
LCM= 48,020
Hence, LCM (28,35,343) is 48,020...
HOPE it helps!!!!✌️
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