Question

11. If n(A) = 5, n(B) = 10, then the minimum and maximum number of elements in
AUB is
a) 5, 10
b) 10, 15
c) 0,5​

Answer 1

Answer:

I hope a is the answer bro and please rate this to get points

Answer 2

Answer:

b)

Step-by-step explanation:

n(AUB)= n(A)+n(B)-n(AnB)

n(AUB) is maximum if n(AnB) is minimum and vice versa.

maximum value taken by n(AnB) =min{n(A),n(B)}

Hence n(AnB) = 5 as n(A)<n(B).

n(AnB) can take the min value =0.

Hence

maximum value of n(AUB)=10+5-0=15

minimum value of n(AUB)=10+5-5=10