Question

11) If sin A = 1/3, then find the value of 9cot^2’A + 9.​

Answer 1

Answer:

If sin A = 1/3, then find the value of 9cot^2’A + 9.

Step-by-step explanation:

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Answer 2

Given:

sin A = 1/3

To find:

The value of 9cot^2’A + 9

Solution:

1) As per the rule of the trigonometric ratios we all know that the ratio of  SinA = P/H

so, P=1 and H=3.

2)To find the value of the base of the triangle we have to apply the Pythagoras theorem.

• P²+B²=H²

• 1²+B²=3²

• B²=8

• B=√8

• B=2√2

CotA = B/P = 2√2/1

3) To find the value of the expression we will put the value of Cot A in the expression.

• 9cot^2’A + 9

• 9(2√2)²+9

• 9×8+9

• 72+9

• 81

The value of 9cot^2’A + 9 is 81