Question

11) If sin A=1/3 then find the value of 9cot^2 A+9 . ​

Answer 1

SinA =1/3
CosecA=1/sinA=3

cosec^2x-cot^2x=1
9-cot^2A=1
Cot^2A=9-1=8
Therefore,
9cot^2A+9=9*8+9=81