Math, asked by poornachandra80, 1 year ago

11. If tan A + cot A = 6, then the value of tan^2 A + cot^2 A is​

Answers

Answered by Anonymous
3

Answer:

Squaring both sides,

(tan A + cot A) ^2= 36

tan^2A + cot^2A + 2 × tan A × cot A = 36

tan^2 A + cot^2 A + 2 = 36

tan^2 A + cot^2 A = 34

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