Question

11. If the area of a square of side 20 cm is equal to the area of a rectangle of length 25 cm, find the .​

Answer 1

$\huge \bold{ \fbox \pink{required \: answer}}$

$\bold{ \underline{ \underline \red{answer}}} →$

16cm

$\bold{ \underline{ \underline \red{solution}}} →$

given :-

• side of square = 20cm
• length of rectangle = 25cm
• area of rectangle = area of square

we know that,

$\bold {area \: of \: square = {side}^{2} \: \: \: \: } \\ \\ \bold{area \: of \: rectangle = l \times b}$

here,

$\bold{area \: of \: square = 20 \times 20} \\ \bold{ \implies a1 = 400 {cm}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

and

$\bold{area \: of \: rectangle = 25 \times b} \\ \bold{ \implies \: a2 = 25b \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } \: \: \: \: \: \: \:$

and according to question;

$\bold{a1 = a2} \\ \bold{\implies \: 400 = 25b } \\ \\ \bold { \implies \: b = \frac{400}{25} } \\ \\ \bold{ \implies \: b = 16cm}$

so, length of rectangle is 16cm

Answer 2

$\bold\red{SolutiOn}$

Given:

• Side of the square of side is 20 cm
• area of triangle is equal to area of square.
• length of rectangle is 25 cm.

$\boxed{\sf{.°.~area~of~square=side²}}$

$\boxed{\sf{area~of~rectangle=L×B}}$

So:

$\sf\pink{Area ~of ~square: 20×20}$

${↪}$$\tt\purple{al:400cm²}$

&

$\sf\orange{Area~of~rectangle:25×b}$

${↪}$$\tt{a2:25b}$

To follow the question:

$\tt{al:a2}$

$\longrightarrow$$\tt{400:25b}$

$\longrightarrow$$\tt{b:\dfrac{\not 400}{\not 25}}$

${⇒}$$\tt{b:16cm}$