Question

11. If the radius height of a cylinder are in the ratio 5:7 and volume is
550sq.cm. The radius is:​

Answer 1

Given:-

•Radius and height of a cylinder are in the ratio 5:7

•Volume of the cylinder=550cm³

To find:-

•Radius of the cylinder

Solution:-

=>Let the radius and height of the cylinder be 5x and 7x respectively

=>We know that volume of a cylinder is :-

$= > \pi {r}^{2} h$

$= > \frac{22}{7} \times 5x \times 5x \times 7x = 550$

=>550x³=550

=>x³=550/550

=>x³=1

=>x=1

Thus,radius of the cylinder is=5×1=5cm

Answer 2

$\huge\purple\star\underline\mathfrak\red{Question :-}\purple\star$

Q. 11. If the radius height of a cylinder are in the ratio 5:7 and volume is

550sq.cm. The radius is:

$\rm\huge\purple\star\underline\pink{Given :-}\purple\star$

• ratio of the the radius and height is 5:7 respectively
• volume of the cylinder is 550cm.sq.

$\rm\huge\purple\star\underline\orange{To \: find :-}\purple\star$

The radius i.e., 5cm

$\huge\purple\star\underline\mathfrak\blue{Explanation :-}\purple\star$

$\green{ \underline \bold{ let \: the \: radius \: and \: the \: height \: is \: 5x \: and \: 7x \: respectively}} \\ \tt: according \: to \: the \: question \: \\ = > h\pi {r}^{2} = 550 {cm}^{2} \\ \tt = > 7x \: \times \frac{22}{7} \times {5x}^{2} = 550 {cm}^{2} \\ \tt = > {x}^{3} = \frac{550}{22 \times 25} \\ \tt = > {x}^{3} = {1}^{3} \\ \tt \: = > x \: = 1cm \\ \tt \: { \therefore} \:radius \: = 5x = 5 \times 1cm \: = 5cm. \\ \tt{\therefore} \: height = 7x \: = 7 \times 1cm \: = 7cm.$