Question

11.If the roots of the equation (b-c)x²(c-a)x+(a-b))=0 are equal then prove that 2b=a+c​

Answer 1

Answer:

proved

Step-by-step explanation:

here a:b-c, b:c-a, c:a-b

if the given equatoin has equal roots

then D : 0

b²-4ac : 0

(c-a)² - 4x(b-a) x(a-b) : 0 ;(c-a)² - (4b-4a) x(a-b) : 0 ;(c-a)² - 4ab+4b²-4a²+4ab : 0 ; (c-a) ²: -4b²+4a² ; (c-a)² : (-2b+2a)² ; c-a : -2b +2a ; 2b : a+c hence proved