11.If x=√3+√2/√3-√2 and y=√3-√2/√3+√2,find the value x^2+y^2
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Step-by-step explanation:
x = √3+√2/√3-√2 ×√3+√2/√3+√2
= (√3+√2)²/3+2. ( a²-b² = (a+b)(a-b))
= 3+2√6+2/1
x = 5+2√6
y = √3-√2/√3+√2×√3-√2/√3-√2
= 5-2√6
x²+y² = (5+2√6)²+(5-2√6)²
= 25 + 24 + 10√6 + 25 + 24 -10√6
= 50+48
= 98...:)
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