Question

11.If x=√3+√2/√3-√2 and y=√3-√2/√3+√2,find the value x^2+y^2​

Answer 1

Step-by-step explanation:

x = √3+√2/√3-√2 ×√3+√2/√3+√2

= (√3+√2)²/3+2. ( a²-b² = (a+b)(a-b))

= 3+2√6+2/1

x = 5+2√6

y = √3-√2/√3+√2×√3-√2/√3-√2

= 5-2√6

x²+y² = (5+2√6)²+(5-2√6)²

= 25 + 24 + 10√6 + 25 + 24 -10√6

= 50+48

= 98...:)