Question

11. If x2 - 4 is a factor of ax^4 + 2x^3 - 3x^2 + bx - 4, then the values of a and b are
1) a = 1, b = - 8
2)a = 3, b = 5
3)a = 6, b = 7
4) a = -1, b = 5
3.​

Answer 1

Answer:

your question is solved

Answer 2

Answer:

1) a = 1 , b = -8

Step-by-step explanation:

x²-4 = (x+2)(x-2)

ax⁴+2x³-3x²+bx-4

By Remainder Theoram,

Putting x = 2,

16a+16-12+2b-4 = 0

16a+2b = 0                       ...... 1

Putting x = -2

16a-16-12-2b-4 = 0

16a-2b = 32                      ....... 2

Adding 1 and 2,

32a = 32

a = 1

b = -8