Question

11. If x2 + y2 = 13 and xy = 6, find the value of the following.
ii. x+4​

Answer 1

Answer:

x + y = 12 and xy = 24

(x + y)2 = x2 + y2 + 2xy

122 = x2 + y2 + 2 × 24

144 = x2 + y2 + 48

x2 + y2 = 96