Question

11. In a A ABC, AB = 9, BC = 10 & AC = 13. Find the length of median AD.

Answer 1

Step-by-step explanation:

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Answer 2

in triangle ABC ,AD is a median

There for, CD = DB

CD = CB ÷2

CD=5

by apollonius theorem,

AC^2 + AB^2 = 2( AD^2 + CD^2 )

13^2 + 9^2 = 2( AD^2 + 5^2)

169 + 81 = 2( AD^2 + 25)

250=2(AD^2+25)

250÷2 = AD^2 + 25

125 - 25 = AD^2

100 = AD^2

AD = √100

AD = 10

length of median is 10