11. In A ABC, ray BD bisects
LABC and ray CE bisects
LACB. If seg AB = seg
AC; then prove that
ED || BC.
Answers
Answered by
7
Answer:
pls mark me as BRAINALIST
Explanation:
Given AB=AC
In △ABC
BD is the bisector of ∠ABC
∴ by using angle bisector property we have
DC
AD
=
BC
AB
.....(1)
and CE is the angle bisector of ∠ACB
∴ by using angle bisector property,
EB
AE
=
BC
AD
....(2)
But segment AB=segment AC ......(3)
From (1),(2) and (3) we have
EB
AE
=
DC
AD
∴segment ED∥segment BC by converse of basic proportionality theorem.
Answered by
2
This is answer
Follow me❣
Attachments:
Similar questions