Question

11 In a triangle ABC, AB = AC, D and E are points on the sides AB and AC respectively
such that BD = CE. Show that:
(i) triangle DBC = triangle ECB
(ii) angle DCB = angle EBC
(iii) OB = OC, where O is the point of intersection of BE and CD.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Step-by-step explanation:

i) triangle DBC = triangle ECB

(ii) angle DCB = angle EBC

(iii) OB = OC, where O is the point of intersection

of BE and CD.

proved above