Question

11. In AABC, D is any point on BC. Prove that : AB + BC + AC > 2 AD.​

Answer 1

Answer:

Step-by-step explanation:

In triangle ABD,

AB+BD>AD [because, the sum of any two sides of a triangle is always greater than the third side]

In triangle ADC,

AC+DC>AD [because, the sum of any two sides of a triangle is always greater than the third side]

Adding these we get,

AB+BD+AC+DC>AD+AD

⇒AB+(BD+DC)+AC>2AD

⇒AB+BC+AC>2AD

Hence proved