Question

11. In AABC, ZB = 90° B is joined to D, the mid-point of AC and
produced to E such that BD = DE. EC is joined. Show that
(1) ∆ADB congruent to ∆CDE
​

Answer 1

Answer:

In triangle ADB and EDC

AD=DC ( Dis mid-point of AC)  

BDA = CDE ( V.O.A)

BE=DE(given)

So, ADB congurent to ECD by SAS... 1

On adding triangle BDC to Triangle ADB and ECD  

ABC= EBC ( adding equal to equals are also equal)

Hence, proved

PLZ MARK AS BRIANLIEST AND THX FOR THE SUPERB QUESTION

Answer 2

Answer:

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