Question

11. In an election, candidate A has secured 12% votes more than candidate B. By how much per cent
has candidate B less than candidate A?
pl help me​

Answer 1

Answer:

Team B has 10 5/7% (10 whole 5 by 7%) less votes than team A.

Step-by-step explanation:

No. of people in an election=y

(Let the total no. of voters be y)

Percentage of candidates team A has secured more than team B=12%

Therefore, No of candidates team B less than team A=

Let total votes for team B = x

Therefore, No. of Votes for team A = x + 12x/100 (x+12=12x)

Total no. of votes for team A = 112x/100(28x/25)

Percentage of team B less than team A=(equation)

(28x/25-x)/28x/25×100

=3x/25 × 25/28x × 100

300/28%

=(150/4%)

={75/7%}

=> 10 5/7% (10 whole 5 by 7%)

Answer= Out of Y(the total population) Team B has got 10 5/7% less votes than team A.