Question

11. In each of the following numbers, replace M by the smallest whole number to make the
resulting number divisible by 3 :
(i) 64 M 3
(ii) 46 M 46 (iii) 27 M 53​

Answer 1

A number is divisible by 3 if sum of digits is divisible by 3

(i) 64M3...for M=0,1 not divisible..

for M=2 sumof digits is 6+4+2+3=15 which is divisible by 3

hence M=3

(ii) 46M46..for M=0 not divisible

for M=1..sum of digits=6+4+1+4+6=21 divisble by 3

hence M=1

(iii) 27M53 for M=0 not div by 3

for M=1, sum of digits =4+6+1+4+6=21 divisible by 3..

hence M=1