11. In fig. 1, MN || BC and AM MB= 1:2, then
ar(A AMN)
ar(A ABC)
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am/mb=an/nc is the right answer
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Given; MN || BC and AM/ MB= 1:2
To Find; In fig. 1, MN || BC and AM /MB= 1:2, then
ar(ΔAMN)/ar(ΔABC)
Solution; we know that the ratio of sides in given then the ratio of areas of triangles can be found out by squaring the ratio of sides
AM/MB=1/2
ar(ΔAMN)/ar(ΔABC) =1/4
Hence the ratio of the area is 1/4
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