Question

11. In Fig 10.24, PQ and XY intersect at O such that PO =OQ and angle p=angle q
prove that triangle POX=triangle QOY.​

Answer 1

Step-by-step explanation:

Given:  PO=OQ

∠P=∠Q

∠XOP=∠YOQ (V.O.A)

⟹ΔPOX≅ΔQOY

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