Question

11. In Fig. 77, DE || QR, AP and BP are bisectors of ZEAB and ZRBA respectively. Find
ZAPB
Fig. 77​

Answer 1

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Answer 2

ᎯᏁᏕᏯᎬᏒ

DE || QR ____(Given)

∠ EAB + ∠RBA = 180° ____(Angles at same side of transversal)

AP and BP are bisectors of ∠EAB and ∠RBA respectively:-

∠ EAB/2+ ∠RBA/2 = 180°/2

∠ BAP + ∠ABP = 90°__________(i)

∠ BAP + ∠ABP + ∠APB = 180° (Angle sum property of triangle)

90° + ∠APB = 180°_____(from i)

∠APB = 180° - 90°

∠APB = 90°