Question

11. In POR, PQ - QR and in PSR, PS = SR.
(a) Is ASPQ = ASRO?
(b) Prove that ZSPO = SRO​

Answer 1

Step-by-step explanation:

Given: in ΔPSR, Q is a point on the side SR such that PQ = PR.

In ΔPRQ,

PR = PQ (given)

⇒ ∠PRQ = ∠PQR (opposite angles to equal sides are equal)

But ∠PQR > ∠PSR (exterior angle of a triangle is greater than each of opposite interior angle) =>∠PRQ > ∠PSR

⇒ PS > PR (opposite sides to greater angle is greater)

⇒ PS > PQ (as PR = PQ)

proved