Question

11. In successive measurements, the readings of the period of a simple pendulum were found to be 2.63 s, 2.56 s, 2.42 s, 2.71 s, and 2.80 s in an experiment. Calculate (i) mean value of the period of oscillation (ii) absolute error in each measurement (iii) mean absolute error (iv) relative error and (3m) (v) percentage error.​

Answer 1

Answer:

The current in the ammeter is given by

i

A

=ε/(r+R

1

+R

2

+R

A

)

The current in R

1

and R

2

without the ammeter is i=ε/(r+R

1

+R

2

). The percent error is then

i

Δi

=

i

i−i

A

=1−

r+R

1

+R

2

+R

A

r+R

1

+R

2

=

r+R

1

+R

2

+R

A

R

A

=

2.0Ω+5.0Ω+4.0Ω+0.10Ω

0.10Ω

=0.90%