11. In the adjoining figure, find the value of sec theta
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in ADC
AC² = DC² + AD²
13² = 5² + AD²
169 = 25 + AD²
169 - 25 = AD²
144 = AD²
AD² = 12²
AD = 12
BD = 21-5
BD = 16
in ABD
h² = b²+ p²
AB² = BD² + AD²
AB² = 16² + 12²
AB² = 256+144
AB² = 400
AB² = 20²
AB = 20
sec thetha = AB/BD
= 20/16
= 5/4
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