Question

11. In the adjoining figure, points P and Q on the side BC of
AABC trisect BC. Prove that
ar (AABQ) = 2ar(AAQC).
Hint. Since points P and Q on side BC trisect BC,
ВО BC and QC - BC.
Moreover, AABQ and AAQC have same height
Use area of a triangle = base x height
2
2
3
Q​

Answer 1

Answer:

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