Physics, asked by nishubegam16, 29 days ago

11. In the experiment of finding 1 point
theocaction time of Sunil, his
friend releases a scale from
rest in between the fingers of
Sunil and notices the scale to
fall by a distance of 20 cm
before being held by Sunil. The
reaction time of Sunil is (Use g
- 10 ms 2) *
O (Q) 0.15
O (
(b) 0.25
O (C) 0.35
0 (d) 0.45​

Answers

Answered by hiturana1978
0

Answer

Open in answr app

Open in answr app(a) When object come closer then image go aways from the lens, 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 f1=1005 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 f1=1005 f=20cm 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 f1=1005 f=20cm When u=−90cm,v = ? 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 f1=1005 f=20cm When u=−90cm,v = ? v1−u1=f1 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 f1=1005 f=20cm When u=−90cm,v = ? v1−u1=f1 v1−−901=201 

Open in answr app(a) When object come closer then image go aways from the lens, So 100cm;60cm;40cm;30cm;24cm (b) When u=−25cm,v=100cm v1−u1=f1 1001−−251=f1 f1=1005 f=20cm When u=−90cm,v = ? v1−u1=f1 v1−−901=201 201=201−901

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