Question

11 In the figure AABC ~ A BPCs. If
ДВР
A B = BC and P is the mid point of seg
BC, then A CADABC) : ACABPQ) =. _________​

Answer 1

Answer:

To prove : - P is midpoint of AC

Proof :- P is midpoint of DB.

Here DP=BP.

∴∠DCP=∠BAP.

and ∠DPC=∠APB

DP=BP

∴ now ΔDPC≅ΔAPB

∴∠CDP=∠PBA

∴AP=PC

∴AP+PC=AC [we know]

2AP=AC

[AP=2AC]

∴P is midpoint of AC