Question

11. In the given figure, AD = DC. Prove that AE + BE > BC. ​

Answer 1

Step-by-step explanation:

AE=DE<br>

<br> BC||AD<br>

<br>

<br> EB=EC<br>

<br>

<br> so, this is a concyclic Quadrilateral<br> In

<br> BC=BC(same)<br> AB=CD(given)<br>

<br>

<br> so, we can say that AC=BD.

Answer 2

Answer:

hii dude

your ans is AC=BD