Question

11. In the given figure, you have two parallelograms;
PQRS and PTUV. If V = 100°, find
V
U
S
R.
P
Q
T
(a) ZP
(b) ZU
(C) ZR (d) ZRSP
1 TECH is such that:​

Answer 1

Answer:

hellow

PQRS is a parallelogram.

PO is angle bisector of ∠P

∴ ∠SPO=∠OPQ --- ( 1 )

QO is an angle bisector of ∠Q

∴ ∠RQO=∠OQP ---- ( 2 )

∴ PS∥QR

⇒ ∠SPQ+∠PQR=180 o

[ Sum of adjacent angles are supplementary ]

⇒ ∠SPO+∠OPQ+∠OQP+∠OQR=180 o

⇒ 2∠OPQ+2∠OQP=180 o

[ From ( 1 ) and ( 2 ) ]

⇒ ∠OPQ+∠OQP=90 o

---- ( 3 )

Now, in △POQ,

⇒ ∠OPQ+∠OQP+∠POQ=180 o

.

⇒ 90 o+∠POQ=180 o

[ From ( 3 ) ]

⇒ ∠POQ=90

I hope this helps you

Answer 2

a quadrilateral efgh is such that