Question

11.IN TRIANGLE ABC, AD is median.
& AB = 8, AC= 15 and AD=8.5 AND FIND BC​

Answer 1

Answer:

Given

AD is the median of △ABC and E is the midpoint of AD

Through D

draw DG∥BF

In △ADG

E is the midpoint ofAD and EF∥DG

By converse of midpoint theorem we have

F is midpoint of AG and AF=FG ..............1

Similarly, in △BCF

D is the midpoint of BC and DG∥BF

G is midpoint of CF and FG=GC ..............2

From equations 1 and 2

we will get

AF=FG=GC ........3

AF+FG+GC=AC

AF+AF+AF=AC (from eu 3)

3AF=AC

AF=

3

1

AC

∴AF=

3

1

×15=5cm