Math, asked by sanjaypathak1378, 4 months ago

11. is the following situation possible? The sum of the ages of two friends is 20 years. Four years
ago the product of their ages (in years) was 48.

Answers

Answered by shababahmmed786
0

Answer:

Let the age of one friend be x\ years.

and the age of another friend will be: (20-x)\ years.

4 years ago, their ages were, x-4\ years and 20-x-4 \ years.

According to the question, the product of their ages in years was 48.

\therefore (x-4)(20-x-4) = 48

\Rightarrow 16x-64-x^2+4x= 48

\Rightarrow -x^2+20x-112 = 0 or \Rightarrow x^2-20x+112 = 0

Now, comparing to get the values of a,\ b,\ c.

a = 1,\ b= -20,\ c =112

Discriminant value D = b^2-4ac = (-20)^2 -4(1)(112) = 400-448 = -48

As D<0.

Therefore, there are no real roots possible for this given equation and hence,

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