Question

11 के लगातार तीन गुणजों का योग 231 है तो उन्हें ज्ञात कीजिए।
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Answer 1

Answer:

66, 77, 88

Step-by-step explanation:

Given The sum of three multiples of 11 is 231 Find out the multiples.

 So let the numbers be 11 x, 11(x + 1), 11(x + 2)

 Now sum will be

 11 x + 11(x + 1) + 11(x + 2) = 231

 11 x + 11 x + 11 + 11 x + 22 = 231

 33 x + 33 = 231

 33 x = 231 - 33

  33 x = 198

   x = 198 / 33

   x = 6

 Now the numbers are

  11 (6), 11(6 + 1), 11(6 + 2)

  66, 77, 88