Question

11. Length of a rectangle is 16 cm less than twice its breadth. If the perimeter of the rectangle is 100cm , find its length and breadth ?​

Answer 1

Given :-

• Length of a rectangle is 16 cm less than twice its breadth. If the perimeter of the rectangle is 100cm

To find :-

• measures of length and breadth

Solution :-

Let the breadth be x then length be 2x

• Perimeter of rectangle = 100cm

→ 2(length + breadth) = 100

→ 2[(2x - 16) + x] = 100

→ 2[2x - 16 + x] = 100

→ 2[3x - 16] = 100

→ 3x - 16 = 100/2

→ 3x - 16 = 50

→ 3x = 50 + 16

→ 3x = 66

→ x = 66/3 = 22

Hence,

• Breadth of rectangle = x = 22cm
• Length of rectangle = 2x = 44cm

Extra Information :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

Solution :

• Let the breadth be x and length be 2x - 16.

• Perimeter = 100 cm (Given)

$</p><p>\underline{ \large \purple{ \mathscr{\dag\:A \bf{ccording} \: to \: \mathscr {Q} \bf{uestion} ....}}}$

Perimeter = 2 (Length + Breadth)

➨100 = 2 (2x - 16 + x)

➨ 100 = 2 (3x - 16)

➨ 100 = 6x - 32

➨ 100 + 32 = 6x

➨ 132 = 6x

➨ x = 132/6

➨ x = 22 cm

Therefore,

$\bullet\:\:\textsf{Breadth = x = \textbf{22 cm}}\\\bullet\:\:\textsf{Length = 2x - 16 = 2(22) - 16 = \textbf{28 cm}}</p><p></p><p></p><p>$