Question

11 liter is filled in a cylindrical vessal of height 35cm . find the diameter of the jar .

Answer 1

AnswEr :

It is given that the height of the cylinderical vessel is 35 cm and filled with 11 litre of juice.

Diagram :

$\setlength{\unitlength}{1 mm}\begin{picture}(5,5)\qbezier(2,3)(8,8)(14,3)\qbezier(2,3)(8,-4)(14,3)\put(2,-27){\line(0,2){30}}\put(14,-27){\line(0,2){30}}\qbezier(2,-27)(8,-35)(14,-27)\qbezier(2,-27)(8,-20)(14,-27)\put(8,-27){\line(0,2){30}}\put(9,-14){ \tt{h} }\put(9,-29){ \tt{} }\put(8,-27){\line(2,0){6}}\put(8,3){\line(2,0){6}}\put(15,-14){ \tt{Height\: = 35cm} }\put(9,-34){ \tt{} }\end{picture}$

⠀⠀⠀⠀⠀$\rule{160}3$

☢ $\underline{\boldsymbol{Let\:us \:calculate\: the\: volume :}}$

1L = 1000cm³

11 L = 11000cm³.

Also,

☆ $\underline{\boldsymbol{By\:using \: formula \: of \: cylinder :}}$

$\implies$ πr²h = 11000

$\implies$ 22/7 × r² × 35 = 11000

$\implies$ 110r² = 11000

$\implies$ r² = 100

$\implies$ r = 10

☆ As we know that 2r = d, where d is the diameter.

$\implies$ 2r = d

$\implies$ 2 × 10 = d

$\implies$ d = 20

Therefore, diameter is 20 cm.

⠀⠀⠀⠀⠀$\rule{160}3$

Answer 2

SoluTion :

• Height = 35 cm
• Quantity of juice = 11 L

Diagram :

$\setlength{\unitlength}{1 mm}\begin{picture}(5,5)\qbezier(2,3)(8,8)(14,3)\qbezier(2,3)(8,-4)(14,3)\put(2,-27){\line(0,2){30}}\put(14,-27){\line(0,2){30}}\qbezier(2,-27)(8,-35)(14,-27)\qbezier(2,-27)(8,-20)(14,-27)\put(8,-27){\line(0,2){30}}\put(9,-14){ \tt{h} }\put(9,-29){ \tt{} }\put(8,-27){\line(2,0){6}}\put(8,3){\line(2,0){6}}\put(15,-14){ \tt{Height\: = 35cm} }\put(9,-34){ \tt{} }\end{picture}$

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☆ $\underline{\boldsymbol{By\:using \: formula \: of \: cylinder :}}$

$\implies$ πr²h = 11000

$\implies$ 22/7 × r² × 35 = 11000

$\implies$ 110r² = 11000

$\implies$ r² = 100

$\implies$ r = 10

☆ Also, 2r = d, where d is the diameter.

$\implies$ 2r = d

$\implies$ 2 × 10 = d

$\implies$ d = 20

• Diameter is 20 cm.

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