Question

11. Mr D' Souza is renovating his house. He has designed two entrances which are as shown in Fig. 14.13. Find the area of each section of the two entrances. ​

Answer 1

Answer:

Given,

Side of a square = 60 m

Length, l = 80 m

According to question,

Perimeter of rectangular field = Perimeter of square field

According to formula,

2(l + b) = 4 × Side

2(80 + b) = 4 × 60

160 + 2b = 240

b = 40

Therefore, Breadth of the rectangle is 40 m.

Now, Area of Square field = (side)2 = (60)2 = 3600 m2

And Area of Rectangular field = length × breadth = 80 × 40 = 3200 m2

Hence, area of square field is larger.