Question

11. Mr. Ram had 9.99,00.000. He gave? 38.47.500 to his son and 5,38,49,700 to his wife
and rest to an orphanage. How much did the orphanage get?
12. Find three consecutive natural numbers whose sum is 1200000​

Answer 1

Answer:

11)amount mr.Ram had=rs9,99,00,000

amount given to his son=rs38,47,500

amount given to his wife=rs5,38,49,700

amount given to orphanage=9,99,00,000-38,47,500+5,38,49,700=9,99,00,000-5,76,97,200=rs4,22,02,800

12)let the 3 numbers be x,x+1 and x+2

x+x+1+x+2=1200000

3x+3=1200000

3x=1111197

x=370399

x+1=370400

x+2=370401

Answer 2

1=>

Let the amount of money donated by Mr. Ram be x.

Equation formed=>

38,47,500+5,38,49,700+x = 9,99,00,000

=>5,76,97,200+x = 9,99,00,000

=> x = 9,99,00,000-5,76,97,200

=> x=4,22,02,800 Answer

Checking

38,47,500+5,38,49,700+4,22,02,800 = 9,99,00,000

=> 9,99,00,000=9,99,00,000

2=>

Let the three consecutive natural numbers be x+1, x+2, x+3.

Equation formed=>

x+1 + x+2 + x+3=12,00,000​

=> 3x+6=12,00,000​

=> 3x=12,00,000​-6

=> 3x=11,99,994

=> x=11,99,994/3

=> x=3,99,998

First consecutive natural number => x+1

= 3,99,998+1

= 3,99,999

Second consecutive natural number => x+2

= 3,99,998+2

= 4,00,000

Third consecutive natural number => x+3

=3,99,998+3

= 4,00,001

Checking =>

x+1+x+2+x+3=12,00,000​

=> 3,99,999+4,00,000+4,00,001=12,00,000​

=> 12,00,000​=12,00,000​

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