Math, asked by shahinparveen610, 3 months ago

11. Neha borrowed 24000 from the State Bank of India to buy a scooter. If the rate of interest
pay alter 2 years?
per annum di
be 10% per annum compounded annually, what payment will she have to make after 2
Fars 3 months?
1
Hint 2 years 3 months = 2 years.
4​

Answers

Answered by hawthornemaci
0

Answer: principal =24000

rate of interest [r]  =10% per annum compounded annually

time [n]  =2 years 3 months  =2+ 3 /12 = 2 +1/4 years

A = P (1 + r/100) ^ n( 1+ [fractional time*rate] /100 )

A = 24000(1 + 10/100) ^ 2( 1+ [1/4*10] /100 )

A = 24000(110/100) ^ 2( 1+ [ {5/2} /100 )

A = 24000*110/100 *110/100 ( 1+ 1/40)

A = 2400*11*11 *41/40

A = 6*11*11 *41

A=29766  ANS

Answered by Princessprincu
1

Answer:

=24000

Rate=10% per annum compounded annually

Time =2 year 3 month=3+

12

2

=2+

4

1

years

A=P(1+

100

r

)

n

(1+[fraction time rate]/100)

=24000(1+

100

10

)

2

(1+[1/4×10]/100)

=24000×(

100

110

)

2

(1+

2

5

×100)

=24000×

100

110

×

100

110

×[1+

40

1

]

=24000×11×11×41/40=6×11×11×41

A=29766

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